Question

(3∫5+425∫1000-1∫200)÷1∫10+6 3∫4+5 1∫2-1∫20=

Answer 1

$1) \frac{3}{5} + \frac{425}{1000} = \frac{600}{1000 } + \frac{425}{1000} = \frac{1025}{1000}$

$2) \frac{1025}{1000} - \frac{1}{200} = \frac{1025}{1000} - \frac{5}{1000} = \frac{1020}{1000}$

$3) \frac{1020}{1000} \div \frac{1}{10} = \frac{1020}{1000} \times \frac{10}{1} = \frac{1020 \times 10}{1000 \times 1} = \frac{1020}{100} = 10 \frac{2}{10}$

$4)10 \frac{2}{10} + 6 \frac{3}{4} = 16 \frac{8 + 30}{40} = 16 \frac{38}{40} = 16 \frac{19}{20}$

$5)16 \frac{19}{20} + 5 \frac{1}{2} = 21 \frac{19 + 10}{20} = 21 \frac{29}{20} = 22 \frac{9}{20}$

$6)22 \frac{9}{20} - \frac{1}{20} = 22 \frac{8}{20} = 22 \frac{4}{10 }$