Question

Помогите,Пожалуйста .алгебра​

Answer 1

$4^{x}-3^{x-0,5}=3^{x+0,5}-2^{2x-1} \\\\4^{x}+2^{2x}*2^{-1}=3^{x+0,5}+3^{x-0,5}\\\\4^{x}+0,5*4^{x}=3^{x}(3^{0,5} +3^{-0,5} )\\\\1,5*4^{x}=\frac{4}{\sqrt{3}}*3^{x}|:1,5\\\\4^{x}=\frac{8}{3\sqrt{3}}*3^{x}|:3^{x}>0\\\\(\frac{4}{3})^{x}=\frac{8}{3\sqrt{3}}\\\\(\frac{2}{\sqrt{3}})^{2x}=(\frac{2}{\sqrt{3}})^{3}\\\\2x=3\\\\x=1,5\\\\Otvet:\boxed{1,5}$