Question

СРОЧНО!!! ПОМОГИТЕ РЕШИТЬ ​

Answer 1

$8Sin^{4}\frac{\alpha}{2}+4Cos\alpha-Cos2\alpha=8(\frac{1-Cos\alpha}{2})^{2}+4Cos\alpha-Cos2\alpha=8*\frac{(1-Cos\alpha)^{2}}{4}+4Cos\alpha-Cos2\alpha=2(1-2Cos\alpha+Cos^{2} \alpha)+4Cos\alpha-Cos2\alpha=2-4Cos\alpha+2Cos^{2}\alpha+4Cos\alpha-Cos2\alpha=2+2Cos^{2}\alpha-Cos2\alpha=2+2Cos^{2}\alpha -(2Cos^{2}\alpha-1)=2+2Cos^{2}\alpha-2Cos^{2}\alpha+1=2+1=3\\\\Otvet:\boxed{3}$