Question

упростить выражение по действиям и подробно 1и 3​ даю 100б

Answer 1

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

Answer 2

$1)\frac{x^{2}+xy}{y^{2}}+1=\frac{x^{2}+xy+y^{2}}{y^{2}}\\\\2)\frac{x^{2}+xy+y^{2}}{y^{2}}:\frac{x^{3}-y^{3}}{y^{3}}=\frac{x^{2}+xy+y^{2}}{y^{2}}*\frac{y^{3}}{(x-y)(x^{2}+xy+y^{2})}=\frac{y}{x-y}\\\\3)\frac{y}{x-y}+\frac{x}{y-x}=\frac{y}{x-y}-\frac{x}{x-y}=\frac{y-x}{x-y}=-1\\\\Otvet:\boxed{-1}$

$1)\frac{a^{2}}{a+b}-\frac{b^{3}}{a^{2}+ab}=\frac{a^{2}}{a+b}-\frac{b^{3}}{a(a+b)}=\frac{a^{3}-b^{3}}{a(a+b)}\\\\2)\frac{a^{2}-b^{2}}{a^{2}+ab+b^{2}}*\frac{a^{3}-b^{3}}{a(a+b)}=\frac{(a-b)(a+b)}{a^{2}+ab+b^{2}}*\frac{(a-b)(a^{2}+ab+b^{2})}{a(a+b)}=\frac{(a-b)^{2}}{a}\\\\3)\frac{(a+b)^{2}}{a}-\frac{(a-b)^{2}}{a}=\frac{a^{2}+2ab+b^{2}-a^{2}+2ab-b^{2}}{a}=\frac{4ab}{a}=4b\\\\Otvet:\boxed{4b}$