Question

Нужен ход решения!!!!!!!!!!!

Answer 1

$1)sqrt{2}sinfrac{13pi}{8}cosfrac{13pi}{8}=frac{sqrt2}{2}sinfrac{26pi}{8}=frac{1}{sqrt2}}sinfrac{13pi}{4}=frac{1}{sqrt2}*-frac{1}{sqrt2}=-0.5\\2)sqrt{75}cos^2frac{7pi}{12}-sqrt{75}sin^2frac{7pi}{12}=sqrt{75}*cosfrac{14pi}{12}=5sqrt{3}*-frac{sqrt3}{2}=-7.5\\3)sqrt{32}cos^2frac{pi}{8}-sqrt8=sqrt8(2cos^2frac{pi}{8}-1)=2sqrt2*cosfrac{pi}{4}=2sqrt2*frac{1}{sqrt2}=2$

$4)sqrt{48}-sqrt{192}sin^2frac{19pi}{12}=sqrt{48}(1-2sin^2frac{19pi}{12})=4sqrt3*cosfrac{38pi}{12}=\=4sqrt3*-frac{sqrt3}{2}=-6$