Question

Решить уравнение.
$frac{4}{ x^{2}+6x+9 }- frac{6}{9- x^{2} } = frac{1}{x-3}$

Answer 1

$4-6=1________ -2 (9- x^{2} ) 2=(х-3)=$

Answer 2

4/(x+3)^2-6/(3-x)(3+x)+1/(3-x)=0
(4(3-x)-6(x+3)+(x+3)^2)/(3-x)(x+3)^2=0
12-4x-6x-18+x^2+9+6x=0
x^2-4x+3=0
x1=3 x2=1
x=1