Question

Помогите срочно!?!?! ​

Answer 1

Ответ:

Объяснение:

(c-2)/(3(c+4)) +c/(c+4)=(c-2+3c)/(3(c+4))=(4с-2)/(3(c+4))=2(2c-1)/(3(c+4))

(b-2)/(2b-6) -(b-1)/(3b-9)=(b-2)/(2(b-3)) -(b-1)/(3(b-3))=(3(b-2)-2(b-1))/(6(b-3))=(3b-6-2b+2)/(6(b-3))=(b-4)/(6(b-3))

4a/(3a-6) +3a/(8-4a)=4a/(3(a-2)) +3a/(4(2-a))=(16a-9a)/(12(a-2))=7a/(12(a-2))

(x+4)/(xy-x²) +(y+4)/(xy-y²)=(x+4)/(x(y-x)) +(y+4)/(y(x-y))=(y(x+4)-x(y+4))/(xy(y-x))=(xy+4y-xy-4x)/(xy(y-x))=4(y-x)/(xy(y-x))=4(x-y)/(xy(x-y))

4/(c²-9) -2/(c²+3c)=4/((c-3)(c+3)) -2/(c(c+3))=(4c-2(c-3))/(c(c-3)(c+3))=(4c-2c+6)/(c(c-3)(c+3))=2(c+3)/(c(c-3)(c+3))=2/(c(c-3))