Question

Памагити:( задания легкие!

Answer 1

Ответ:

1)9ab²/2 : 3a³b/4 = (9ab² × 4) : (2 × 3a²b) = 2 × 3b/a²

2)4a/7 : a/49 = (4a × 49) : 7a = (4 × 49) : 7 = 196 : 7 = 28

3)9x²/4y² : 3x²/20y = (9x² × 20y) : (4y² × 3x²) = 3 × 5/y = 15/y

4)ax - ay/10c : bx - by/15c² = a(x - y)/10c : b(x - y)/15c² = a × 3c/2 = 3ac/2

5)x² - 25y²/3 : 2x - 10y/5 = (x - 5y)(x + 5y)/3 × 5/2(x - 5y) = 5(x + 5)/3 × 2 = 5(x + 5)/6

6)x² - 2xy + y²/24 : x - y/8 = (x - y)²/24 × 8/x - y = x - y/3