Question

3x^3-x^2-8x=0 решите уравнение!!!! ​

Answer 1

Объяснение:

$3x ^{3} - x^{2} - 8x = 0 \\ x(3 {x}^{2} - x - 8) = 0 \\ x = 0 \\ 3 {x}^{2} - x - 8 = 0 \\ d = 1 - 4 \times ( - 8) \times 3 = 1 + 96 = 97 \\ x = \frac{1 + \sqrt{97} } {6} \\ x = \frac{1 - \sqrt{97} }{6}$