Question

Решить неравенство |x+7|<5
|3-5x|_<1

Answer 1

$1)$

$|x+7|<5$

$-5<x+7<5$

$-5-7<x+7-7<5-7$

$-12<x<-2$

Ответ: х∈(-12;  -2)

$2)$

$|3-5x|\leq 1$

$-1\leq 3-5x\leq 1$

$-1-3\leq 3-5x-3\leq 1-3$

$-4\leq -5x\leq -2$$-4*(-\frac{1}{5})\geq -5x*(-\frac{1}{5}) \geq -2*(-\frac{1}{5})$

$\frac{2}{5}\leq x\leq \frac{4}{5}$

$0,4\leq x\leq 0,8$

Ответ: х∈[0,4;  0,8]