Question

ПОМОГИТЕ ПОЖАЛУЙСТА.
(КОТОРЫЕ В КРУЖКАХ)

Answer 1

Ответ:

Д) $\frac{( - 3a + 3) {}^{2} }{9(a {}^{2} + 1)(a - 1) {}^{3} } \\ \frac{( - 3(a - 1)) { }^{2} }{9(a {}^{2} + 1)(a - 1) {}^{3} } \\ \frac{( - 3) {}^{2}(a - 1) {}^{2} }{9(a {}^{2} + 1)(a - 1) {}^{3} } \\ \frac{3 {}^{2} }{9(a {}^{2} + 1)( a - 1)} \\ \frac{9}{9(a {}^{2} + 1)(a - 1)} \\ \frac{1}{(a {}^{2} + 1)(a - 1)} \\ \frac{1}{a {}^{3} - a {}^{2} + a - 1 }$

Е) $\frac{(b - 6)(b + 6)}{4(b + 6)} \\ \frac{b - 6}{4}$

В) $\frac{a(a {}^{2} - 4) }{ab {}^{2} } + 2b {}^{2} \\ \frac{a {}^{2} - 4 }{b {}^{2} } + 2b {}^{2} \\ \frac{a {}^{2} - 4 + 2b {}^{2} }{b {}^{2} }$

Г) $\frac{(a - 3)(a + 3)(b + 7)}{(a - 3)b - (b {}^{2} - 49)} \\ \frac{(a + 3)(b + 7)}{b(b - 7)(b + 7)} \\ \frac{a + 3}{b(b - 7)} \\ \frac{a + 3}{b {}^{2} - 7b }$

В) $33b {}^{4} 2 {}^{8} \div (24 \times 2 {}^{17} b {}^{2} ) \\ \frac{33b {}^{4} - 2 {}^{8} }{24 \times 2 {}^{17} b {}^{2} } \\ \frac{11b {}^{2} }{8 \times 2 {}^{9} } \\ \frac{11b {}^{2} }{2 {}^{3} \times 2 {}^{9} } \\ \frac{11b {}^{2} }{2 {}^{12} } \\ \frac{11b {}^{2} }{4096}$

Г) $\frac{54a {}^{7}b {}^{12} c {}^{5} }{42a {}^{3}b {}^{15}c {}^{3} } \\ \frac{9a {}^{4}c {}^{2} }{7b {}^{3} }$