Question

3) 0,7ax - bx + 0,7ay - by;
4)2/3by-ay+2/3bx-ax
5)5/6a-ax+5/6b-bx
6)7/8ax-a+7/8bx-b???
​

Answer 1

Ответ:

3) 0,7ax - bx + 0,7ay - by = x(0,7a-b)+y(0,7a-b)=(x+y)(0,7a-b)

4) 2/3by-ay+2/3bx-ax = x(2/3b-a)+y(2/3b-a)=(x+y)(2/3b-a)

5) 5/6a-ax+5/6b-bx = a(5/6-x)+b(5/6-x)=(a+b)(5/6-x)

6) 7/8ax-a+7/8bx-b = a(7/8x-1)+b(7/8x-1)=(a+b)(7/8x-1)

Пошаговое объяснение: