Question

Всё решите пж срочно надо

Answer 1

Ответ:

1) X=1 2)x=-$\frac{7}{17}$  3)x=1        4)$x_{1} =-22 , x_{2}=16$   5)$k_{1} =-\frac{5}{3} , k_{2} =6$

Объяснение:

1)$\frac{6x-4}{3} -\frac{3x-2}{6} =\frac{2x-1}{2} \\2(6x-4)-(3x-2)=3(2x-1)\\12x-8-3x+2=6x-3\\9x-6=6x-3\\9x-6x=-3+6\\3x=3\\x=1$

2)$\frac{2x-3}{4} -\frac{5x+1}{8} =2x\\2(2x-3)-(5x+1)=16\\4x-6-5x-1=16x\\-x-7=16x\\-x-16x=7\\-17x=7\\x=-\frac{7}{17}$

3) $\frac{2x-1}{2} -\frac{3-4x}{4} -\frac{3-5x}{8} =1\\4(2x-1)-2(3-4x)-(3-5x)=8\\8x-4-6+8x-3+5x=8\\21x-13=8\\21x=8+13\\21x=21\\x=1$

4) $|x+3|=19\\\left \\ {{x+3=19} \atop {x+3=-19}} \right. \\\left \ {{x=16} \atop {x=-22}} \right. \\x_{1} =-22 ,  x_{2} =16$

5) (3k=5)(k-6)=0

$\left \ {{3k+5=0} \atop k-6=0}} \right. \\\left \ {{k=-\frac{5}{3} } \atop {k=6}} \right. \\k_{1} =-\frac{5}{3} , k_{2} =6$