Question

Выполните деление алгебраических дробей:

Answer 1

$\frac{(u-1)^{2}}{100+100u^{3}}:\frac{1-u^{2}}{(10u+10)^{2}}=\frac{(u-1)^{2}}{100(1+u^{3})}:\frac{(1-u)(1+u)}{100(u+1)^{2}}=\frac{(u-1)^{2}}{100(1+u)(1-u+u^{2})}*\frac{100(u+1)}{1-u}=\frac{1-u}{u^{2}-u+1}\\\\Otvet:\boxed{\frac{1-u}{u^{2}-u+1}}$

Answer 2

Решение на фото/////