Question

2x^2-2y^2-x+y/1-2x-2y =​

Answer 1

Ответ:

$\frac{2x {}^{2} - 2y {}^{2} - x + y }{1 - 2x - 2y} = \frac{2(x {}^{2} - y {}^{2} ) - (x - y) }{ - (2x + 2y - 1)} = \frac{2(x - y)(x + y) - (x - y)}{ - (2x + 2y - 1)} = \frac{(x - y)(2(x + y) - 1)}{ - (2x + 2y - 1)} = \frac{(x - y)(2x + 2y - 1)}{ - (2x + 2y - 1)} = (x - y )\times ( - 1) = - x + y$