Question

Решите пожалуйстадпддпщпзп​

Answer 1

Ответ:

$a) \frac{9x}{ {10b}^{2} } \times \frac{ {5b}^{3} }{3 {x}^{3} } = \frac{3b}{ 2{x}^{2} }$

$\frac{3}{ {a}^{2} - 4 {b}^{2} } \times (3a + 10b) = \\ = \frac{3(3a + 10b)}{ {a}^{2} - {4b}^{2} } = \frac{9a + 30b}{ {a}^{2} - 4 {b}^{2} }$

$( - \frac{3a}{4 {b}^{3} } ) {}^{2} = \frac{9 {a}^{2} }{16 {b}^{6} }$