Question

сделайте пж плиииз умоляю​

Answer 1

Пошаговое объяснение:

$\tt\displaystyle\[\left( {3 + \frac{1}{{\frac{5}{{12}} + \frac{1}{3}}}} \right) + \left( {2 + \frac{1}{{3 + \frac{3}{4}}}} \right) - \left( {1 +\frac{1}{{1 + \frac{2}{3}}}} \right) = \left( {3 + \frac{1}{{\frac{5}{{12}} + \frac{4}{{12}}}}} \right) +\left( {2 +\frac{1}{{\frac{{12}}{4} + \frac{3}{4}}}} \right) - \left( {1 + \frac{1}{{\frac{3}{3} + \frac{2}{3}}}} \right) = \]$

$\tt\displaystyle \[=\left( {3 + \frac{1}{{\frac{9}{{12}}}}} \right) + \left( {2 + \frac{1}{{\frac{{15}}{4}}}} \right) - \left( {1 + \frac{1}{{\frac{5}{3}}}} \right) = \left( {3 + \frac{{12}}{9}} \right) + \left( {2 + \frac{4}{{15}}} \right) - \left( {1 + \frac{3}{5}} \right) =\]$

$\tt\displaystyle\[ = \left( {\frac{{27}}{9} + \frac{{12}}{9}} \right) + \left( {\frac{{30}}{{15}} + \frac{4}{{15}}} \right) - \left( {\frac{5}{5} + \frac{3}{5}} \right) = \frac{{39}}{9} + \frac{{34}}{{15}} - \frac{8}{5} =\frac{{195}}{{45}} + \frac{{102}}{{45}} - \frac{{72}}{{45}} = \frac{{225}}{{45}} = 5\]\]$