Question

(2-√3)²(7+4√3)-4√3(целых)1/16= ?​

Answer 1

$(2-\sqrt3)^2(7+4\sqrt3)-4\sqrt{3\frac{1}{16}}=\\\\=(4-4\sqrt3+3)(7+4\sqrt3)-4\sqrt{\frac{49}{16}}=\\\\=(7-4\sqrt3)(7+4\sqrt3)-4\cdot \frac{7}{4}=\\\\=49-16\cdot 3-7=1-7=-6$