Question

Решить показательное уравнение

Answer 1

$4^{x^{2}-x }-10*2^{x^{2}}+2^{2x+4}=0\\\\  2^{2x^{2}}*2^{-2x}-10*2^{x^{2}}+2^{2x}*2^{4}=0\\\\\frac{2^{2x^{2}} }{2^{2x}}-10*2^{x^{2}}+16*2^{2x}=0|*2^{2x}>0\\\\2^{2x^{2}}-10*2^{x^{2}}*2^{2x}+16*2^{2x}*2^{2x}=0\\\\(2^{x^{2}}-8*2^{2x})(2^{x^{2}}-2*2^{2x})=0\\\\\left[\begin{array}{ccc}2^{x^{2}}-8*2^{2x}=0 \\2^{x^{2}}-2*2^{2x}=0  \end{array}\right\\\\1)2^{x^{2}}-8*2^{2x}=0\\\\2^{x^{2}}=8*2^{2x}|:2^{2x}>0\\\\2^{x^{2}-2x}=8\\\\2^{x^{2}-2x }=2^{3}$

$x^{2}-2x=3\\\\x^{2}-2x-3=0\\\\x_{1}=3\\\\x_{2}=-1\\\\2)2^{x^{2}}-2*2^{2x}=0\\\\2^{x^{2}}=2*2^{2x}|:2^{2x}>0\\\\2^{x^{2}-2x }=2\\\\x^{2}-2x=1\\\\x^{2} -2x-1=0\\\\(x-1)^{2}=0\\\\x_{3}=1\\\\Otvet:\boxed{-1;1;3}$