Question

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Answer 1

$\frac{x^2-16}{x^2-8x+16}=\frac{(x-4)(x+4)}{(x-4)^2}=\frac{x+4}{x-4}\\\\\\\frac{5}{c+3}-\frac{5c-2}{c^2+3c}=\frac{5}{c+3}-\frac{5c-2}{c(c+3)}=\frac{5c-(5c-2)}{c(c+3)}=\frac{2}{c^2+3c}$

Answer 2

$1)\frac{x^{2}-16}{x^{2}-8x+16 }=\frac{(x-4)(x+4)}{(x-4)^{2}}=\frac{x+4}{x-4}\\\\2)\frac{5}{c+3}-\frac{5c-2}{c^{2}+3c }=\frac{5}{c+3}-\frac{5c-2}{c(c+3)}=\frac{5c-5c+2}{c(c+3)}=\frac{2}{c^{2}+3c}$