Question

Помогите пожалуйста!!

Answer 1

Ответ:

1)

${4}^{x} = 64 \\ x = 3$

2)

${25}^{x} = \frac{1}{5} \\ x = - \frac{1}{2}$

3)

${3}^{2x} = 1 \\ 2x = 0 \\ x = 0$

4)

${3}^{ {x}^{2} - 5x - 10 } = 1 \\ {x}^{2} - 5x - 10 = 0 \\ d = 25 + 40 = 65 \\ \sqrt{d} = \sqrt{65} \\ x = \frac{5 + \sqrt{65} }{2} \\ x = \frac{5 - \sqrt{65} }{2}$

5)

${3}^{6 - x} = 3 \\ 6 - x = 1 \\ x = 5$

6)

${3}^{ {x}^{2} - x - 2 } = 81 \\ {x}^{2} - x - 2 = 4 \\ {x}^{2} - x - 6 = 0 \\ d = 1 + 24 = 25 \\ \sqrt{d} = \sqrt{25} = 5 \\ x = \frac{1 + 5 }{2} = 3 \\ x = \frac{1 - 5 }{2} = - 2$

Answer 2

Ответ: во вложении Пошаговое объяснение: