Question

пажалуста помогите решить​

Answer 1

Ответ:

Вот:

Объяснение:

a) $\frac{4a + 7}{-(a^{-2}-2a+ 4)} * \frac{(a+2)*(a^{2}-2a+4 )}{6a*(4a+7)} \\\\\frac{(a+2)*(-1)}{6a} \\-\frac{a+2}{6a}$

б) $3(8y^{2} -18)*\frac{7y}{3(4y^{2}-12y+9)} \\2(4y^{2} -9)*\frac{7y}{(2y-3)^{2} } \\2(2y+3)(2y-3)*\frac{7y}{(2y-3)^{2} } \\2(ay+3)*\frac{7y}{2y-3}\\\frac{2(2y+3)*7y}{2y-3}\\\frac{28y^{2} +42y}{2y-3}$

в) $\frac{m^{2}}{m^{2}-1} *\frac{(1-m^{2})(1+m^{2})}{m(3m^{2}+3)}\\\frac{m}{m^{2}-1}*\frac{-(m^{2}-1)(1+m^{2})}{3(m^{2}+1)}  \\ -\frac{m}{3}$

г) $-\frac{16p^{8} }{49q^{10}}*\frac{91q^{8}}{72p^{7}}\\ - \frac{2p}{7q^{2}} *\frac{13}{9}\\ - \frac{26p}{63q^{2}}$