Question

Прошу помогите пожалуйста!!!!

Answer 1

$\frac{x^{2}-6x+9}{x^{2}-9}=\frac{(x-3)^{2}}{(x-3)(x+3)}=\frac{x-3}{x+3}\\\\\frac{-1\frac{1}{3}-3}{-1\frac{1}{3}+3}=-4\frac{1}{3}:1\frac{2}{3}=-\frac{13}{3}:\frac{5}{3}=-\frac{13}{3}*\frac{3}{5}=-\frac{13}{5}=-2,6\\\\Otvet:\boxed{-2,6}$