Question

ПОМОГИТЕ С УРАВНЕНИЯМИ ЗА 8 КЛАСС
ДАМ 98 БАЛЛОВ

Answer 1

1) $\frac{a-18}{2a-12} - \frac{a-6}{2a+12} + \frac{50}{a^2-36} = \frac{a-18}{2(a-6)} - \frac{a-6}{2(a+6)} + \frac{50}{(a+6)(a-6)} = \frac{(a-18)(a+6)-(a-6)(a-6)+2*50}{2(a+6)(a-6)} = \frac{a^2-12a-108-a^2+12a-36+100}{2(a+6)(a-6)} = \frac{-44}{2(a+6)(a-6)} = \frac{-22}{a^2-36}$

2) $\frac{6c^3+3c}{c^3-1} - \frac{3c^3}{c^2+c+1} = \frac{3c(2c^2+1)}{(c-1)(c^2+c+1)} - \frac{3c^3}{c^2+c+1} = \frac{3c(2c^2+1)-3c*c^2}{(c-1)(c^2+c+1)} = \frac{3c(c^2+1)}{c^3-1}$