Question

Помогите решить номер 2

Answer 1

x⁴ = 4   ⇒   x² = 2

$\frac{2}{(x-2)(x-1)(x+1)(x+2)}=\frac{2}{[(x-2)(x+2)][(x-1)(x+1)]}=\frac{2}{(x^{2}-4)(x^{2}-1)}=\frac{2}{x^{4}-x^{2}-4x^{2}+4} =\frac{2}{x^{4}-5x^{2}+4}=\frac{2}{4-5*2+4}=\frac{2}{-2}=-1\\\\Otvet:\boxed{-1}$