Question

Помогите пожалуйста с математикой

Answer 1

57.

$4x^2-25 = (2x + 5)(2x - 5)\\\\81p^2 - 9q^2 = (9p+3q)(9p-3q)\\\\36m^2 - 4n^2 = (6m - 2n)(6m + 2n)\\\\25 - x^2y^2 = (5 - xy)(5 + xy)\\\\a^2b^2 - 9b^2 = (ab - 3b)(ab + 3b)\\\\\frac{16}{25} - \frac{4m^2}{9} = (\frac{4}{5} -\frac{2m}{3})(\frac{4}{5} +\frac{2m}{3})\\\\\frac{81}{121y^2} - 0,49 = (\frac{9}{11y} - 0,7)(\frac{9}{11y} + 0,7)$

$100c^2-0,01 = (10c - 0,1)(10c + 0,1)\\\\16g^4 - 49d^2 = (4g^2 - 7d)(4g^2 + 7d)\\\\2,25x^2 - 0,04y^2 = (1,5x - 0,2y)(1,5x + 0,2y)\\\\1 - 64w^2 = (1-8w)(1+8w)\\\\(x+y)^2-y^2 = (x+y - y)(x+y+y) = x^2 + 2xy\\\\\frac{1}{4}a^2 - \frac{1}{9}b^2 = (\frac{1}{2}a - \frac{1}{3}b)(\frac{1}{2}a + \frac{1}{3}b)\\\\\frac{169p^2}{k^4}  - \frac{n^4m^2}{16} = (\frac{13p}{k^2}-\frac{n^2m}{4})(\frac{13p}{k^2}+\frac{n^2m}{4})$