Question

уравнение 11(2х+6)+4 (3х+7х)=378

Answer 1

Ответ:

$11(2x + 6) + 4(3x + 7x) = 378 \\ 22x + 66 + 12x + 28x = 378 \\ 22x + 12x + 28x = 378 - 66 \\ 62x = 312 \\ x = 312 \div 66 \\ x = 5 \frac{2}{66} = 5 \frac{1}{33}$