Question

очень срочно! пожалуйста помогите упростить!​

Answer 1

$\frac{9m^2-3mn}{18m^2-2n} = \frac{3m(3m-n)}{2(9m^2-n)}\\\\\frac{d}{2d^2-7} - \frac{d}{7-2d^2} = \frac{d - (-d)}{2d^2-7} = \frac{2d}{2d^2-7}\\\\\frac{6}{kt} - \frac{2}{t} = \frac{6}{kt} - \frac{2k}{kt} = \frac{6-2k}{kt}\\\\\frac{3}{2m} + \frac{2}{7m} - \frac{3m}{14} = \frac{21}{14m} + \frac{4}{14m} - \frac{3m^2}{14m} = \frac{-3m^2+25}{14m}$

$\frac{a^2+b^2}{4a^2-b^2} - \frac{2a+b}{3(2a-b)} = \frac{(a^2+b^2)*3}{3(2a-b)(2a+b)} - \frac{(2a+b)(2a+b)}{3(2a-b)(2a+b)} = \frac{3a^2+3b^2 + 4a^4+4a^2b^2+b^4}{3(2a-b)(2a+b)} = \frac{4a^4+4a^2b^2+b^4+3a^2+3b^2}{3(2a-b)(2a+b)}$