Question

Помогите 1,2 задание пожалуйста!!!!

Answer 1

Ответ:

Объяснение:

1.

a)    39x³y/26x²y²=1,5x/y

b)

5y/(y²-2y)=   5y/((y(y-2))= 5/(y-2)

c)

(3a-3b)/(a²-b²)=    3(a-b)/(a-b)(a+b)=3/(a+b)

2.

a)

(3-2a)/2a  - (1-a²/a ) =  [a(3-2a)-2(1-a²)]/2a² = (3a-6a²-2+2a²)/2a²=

=(-4a²+3a-2)/2a²

b)

1/(3x+y) - 1/(3x-y) =[3x-y-(3x+y)/(9x²-y²)= (3x-y-3x-y)/(9x²-y²)=

=-2y/(9x²-y²)

c)

(4-3b)/(b²-2b) +3/(b-2)=   (4-3b)/b(b-2)  + 3/(b-2)=(4-3b+3b)/b(b-2)=

=4/(b²-2b)