Question

Помогите с 3 и 4 пожалуйста!!!!

Answer 1

$3)(\sqrt{5})^{2}=5\\\\(3\sqrt{2})^{2}=3^{2}(\sqrt{2})^{2}=9*2=18\\\\(-\sqrt{3,7})^{2}=3,7\\\\4)\sqrt{32} *\sqrt{2}=\sqrt{32*2}=\sqrt{64}=\sqrt{8^{2}}=8\\\\\frac{\sqrt{180}}{\sqrt{20}} =\sqrt{\frac{180}{20}} =\sqrt{9} =\sqrt{3^{2}}=3$