Question

а/а-b + a^2+b^2/b^2-a^2

Answer 1

$\frac{a}{a-b}+\frac{a^{2}+b^{2}}{b^{2}-a^{2}}+\frac{a}{a+b}=\frac{a}{a-b}-\frac{a^{2}+b^{2}  }{(a-b)(a+b)}+\frac{a}{a+b}=\frac{a^{2}+ab-a^{2}-b^{2}+a^{2}-ab}{(a-b)(a+b)}=\frac{a^{2}-b^{2}}{a^{2}-b^{2}}=1\\\\Otvet:\boxed{1}$