Question

2xy^2/8x^2y^2 б) a-3/a^2-6a+9 помогите решить

Answer 1

$\displaystyle \tt a). \ \ \frac{2xy^{2}}{8x^{2}y^{2}}=\frac{2xy^{2}}{2xy^{2}\cdot4x}=\frac{1}{4x};\\\\\\b). \ \ \frac{a-3}{a^{2}-6a+9}=\frac{a-3}{(a-3)^{2}}=\frac{1}{a-3};$