Question

Помогите , решите задания с 3.3-3.6 (четные)

Answer 1

Відповідь: 1) √360 × √490 = √176400 = 420

2) √32 × √72 = √2304 = 48

3) √125 × √80 = √10000 = 100

4) √3.6 × √810 =√2916 = 54

5) √275625 = 525

6) √331776 = 576

7) √45 × √80 × √0.16 = √576= 24

8)√98 × √24 × √27 = √63504 = 252

Пояснення:

Answer 2

Ответ:

3.3.

$2) \sqrt{32*72} = \sqrt{8*4*8*9} = 8*2*3 = 48\\\\4) \sqrt{3,6*810} = \sqrt{36*0,1*81*10} = \sqrt{36*81} = 6*9 = 54\\\\6) \sqrt{331776} = \sqrt{20736*16} = \sqrt{576*36*16} = \sqrt{36*16*36*16} = 6*4*6*4 = 24*24 = 576\\\\8) \sqrt{98*24*27} = \sqrt{49*2*2*12*3*9} = \sqrt{49*12*12*9} = 7*12*3 = 252$

3.4.

$2) \sqrt{4^2+8^2} = \sqrt{16+64} = \sqrt{80}\\\\4 + 8 = 12 = \sqrt{144}\\\\\sqrt{4^2+8^2} < 4 + 8\\\\4) \sqrt{21,8^2 - 18,2^2} = \sqrt{(21,8-18,2)(21,8+18,2)} = \sqrt{3,6*40} = \sqrt{36*4} = 6*2 = 12\\\\21,8-18,2 = 3,6\\\\\sqrt{21,8^2 - 18,2^2} > 21,8 - 18,2$

3.5.

$2) \sqrt{6,8^2-3,2^2} = \sqrt{(6,8-3,2)(6,8+3,2)} = \sqrt{3,6*10} = \sqrt{36} = 6\\\\4) \sqrt{3,13^2 - 3,12^2} = \sqrt{(3,13-3,12)(3,13+3,12)} = \sqrt{0,01*6,25} \\\\= 0,1*2,5 = 0,25$

3.6.

$2) \sqrt{7xa} = \sqrt{7}*\sqrt{x}*\sqrt{a}\\\\4) \sqrt{15c} = \sqrt{5}*\sqrt{3}*\sqrt{c}\\\\6) \sqrt{1,5y} = \sqrt{3} * \sqrt{0,5} * \sqrt{y}$