Question

x²-3x-4=0
2x²-8=0
6x²-12x
${x}^{2} - 2x - 3 > 0$
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Answer 1

1) Д=9-4*1*(-4)=25

х1=(3+5)/2=4

х2=(3-5)/2=-1

2) 2х^2=8

х^2=4

х1=2

х2=-2

3) 6х(х-2)=0

6х=0

х=0

или х-2=0

х=2

4) Д=4+4*3=16

х1=(2+4)/2=3

х2=(2-4)/2=-1

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(-беск, - 1), (3,+беск)