Question

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Answer 1

$\tt\displaystyle B)~\Big(0,5-\frac{1}{3}+0,25-\frac{1}{5}\Big):\Big(0,25-\frac{1}{6}\Big)\cdot\frac{7}{13}=\\\\\\=\Big(\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5} \Big):\Big(\frac{1}{4}-\frac{1}{6}\Big)\cdot\frac{7}{13}=\\\\\\=\Big(\frac{30-20+15-12}{60} \Big):\Big(\frac{3-2}{12}\Big)\cdot\frac{7}{13}=\\\\\\=\frac{13}{60}:\frac{1}{12}\cdot\frac{7}{13}=\frac{13\cdot12\cdot7}{60\cdot1\cdot13}=\frac{1\cdot1\cdot7}{5\cdot1}=\\\\\\\frac{7}{5}=1\frac{2}{5}$