Question

решить неравенство
$\sqrt{ {5x}^{2} - 4x - 1} < \sqrt{11}$
​

Answer 1

=>

5x^2-4x-1<11

5x^2-4x-12<0

D=16-4*5*(-12)=256=16^2

X1 = (4+16)/2*5 = 2

X2 = (4-16)/2*5 =-6/5