Question

ПОМОГИТЕ! ПРОШУ, ПОЖАЛУЙСТА

Answer 1

$5)\sqrt[8]{\sqrt{11}}=\sqrt[16]{11}\\\\\sqrt[3]{27*64}=\sqrt[3]{3^{3}*4^{3}}=3*4=12\\\\6)\sqrt[9]{6^{2}}=6^{\frac{2}{9}}\\\\\sqrt[61]{c^{4}}=c^{\frac{4}{61}}\\\\\sqrt[8]{12^{3}}=12^{\frac{3}{8}}\\\\7)\frac{4}{\sqrt{10}-\sqrt{2}}=\frac{4*(\sqrt{10}+\sqrt{2})}{(\sqrt{10}-\sqrt{2})(\sqrt{10}+\sqrt{2})}=\frac{4(\sqrt{10}+\sqrt{2})}{(\sqrt{10})^{2}-(\sqrt{2})^{2}}=\frac{4(\sqrt{10}+\sqrt{2})}{10-2}=\frac{4(\sqrt{10}+\sqrt{2})}{8}=\frac{\sqrt{10}+\sqrt{2}}{2}$