Question

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упростите, используя формулу. фото ниже.

Answer 1

$1)\sqrt{6+2\sqrt{5}}-\sqrt{5}=\sqrt{5+2\sqrt{5}+1}-\sqrt{5}=\sqrt{(\sqrt{5}+1)^{2}}-\sqrt{5  }=|\sqrt{5}+1|-\sqrt{5}=\sqrt{5}+1-\sqrt{5}=1\\\\Otvet:\boxed{1}\\\\2)\sqrt{3}-\sqrt{7+4\sqrt{3}}=\sqrt{3}-\sqrt{4+4\sqrt{3}+3}=\sqrt{3}-\sqrt{(2+\sqrt{3})^{2}}=\sqrt{3}-|2+\sqrt{3}|=\sqrt{3}-(2+\sqrt{3})=\sqrt{3}-2-\sqrt{3}=-2\\\\Otvet:\boxed{-2}$

$\sqrt{9-2\sqrt{14}}+\sqrt{9+2\sqrt{14}}=\sqrt{7-2\sqrt{14}+2}+\sqrt{7+2\sqrt{14}+2}=\sqrt{(\sqrt{7}-\sqrt{2})^{2}}+\sqrt{(\sqrt{7}+\sqrt{2})^{2}}=|\sqrt{7}-\sqrt{2}|+|\sqrt{7}+\sqrt{2}|=\sqrt{7}-\sqrt{2}+\sqrt{7}+\sqrt{2}=2\sqrt{7}\\\\Otvet:\boxed{2\sqrt{7}}$

$4)\sqrt{23+8\sqrt{7}}-\sqrt{23-8\sqrt{7}}=\sqrt{16+8\sqrt{7}+7}-\sqrt{16-8\sqrt{7}+7}=\sqrt{(4+\sqrt{7})^{2}}-\sqrt{(4-\sqrt{7})^{2}}=|4+\sqrt{7}|-|4-\sqrt{7}|=(4+\sqrt{7})-(4-\sqrt{7})=4+\sqrt{7}-4+\sqrt{7}=2\sqrt{7}\\\\Otvet:\boxed{2\sqrt{7}}$