Question

x²-16 x²-9
--------- · ------
x³-3x² x²+4x

Answer 1

(x²-16)*( x²-9)/((x³-3x²) (x²+4x))=((х-4)(х+4)(х-3)(х+3))/(х²*(х-3)*х*(х+4))=

(х-4)*(х+3)/х³=(х²-х-12)/х³