Question

Помогите решить! Буду благодарен.См.скрин

Answer 1

$[tex] frac{m-8}{5m} / frac{m^{2}-64}{15m^{2}}= frac{m-8}{5m} * frac{15m^{2}}{(m-8)(m+8)} = frac{3m}{m+8}; ( frac{a^{-3}b^{2}}{2c} ) ^{2}* frac{2c^{3} a^{6}}{b^{3}}= frac{b^{4}2c^{3}a^{6}}{a^{6}4c^{2}b^{3}}= frac{bc}{2}$[/tex]

$64x+x^{-1}=-16; 64x+ frac{1}{x} +16=0; 64x^{2}+1+16x=0; (8x+1)^{2}=0; 8x+1=0; x=- frac{1}{8}$

$frac{ 2^{5} 0,5 ^{-6} }{16 ^{3} }= frac{ 2^{5} 10 ^{6} }{ 5^{6} (2*8) ^{3} } = frac{2^{5} (2*5) ^{6}}{5^{6} 2 ^{12} }= frac{2^{6} 5 ^{6}}{5^{6} 2 ^{12} }= frac{1}{ 2^{6}} = 2^{-6}$

$( frac{c-2}{c+2}- frac{c}{c-2} )* frac{c+2}{2-3c}= frac{ c^{2} -4c+4- c^{2}-2c }{(c-2)(c+2)} * frac{c+2}{2-3c}= frac{-6c+4}{(c-2)(2-3c)} = frac{2}{c-2}$

Answer 2

Спасибо!!!