Question

Приведите дроби к обшему знаменателю ​

Answer 1

$1)\; \; \frac{2a-1}{a-4}=\frac{2(2a-1)}{2(a-4)}\; \; ;\; \; \frac{3a+2}{2a-8}=\frac{3a+2}{2(a-4)}\; ;\\\\2)\; \; \frac{x+2}{3x+9}=\frac{x+2}{3(x+3)}=\frac{5(x+2)}{15(x+3)}\; \; ;\; \; \frac{4-x}{5x+15}=\frac{4-x}{5(x+3)}=\frac{3(4-x)}{15(x+3)}\; ;\\\\3)\; \; \frac{m+1}{m-3}=\frac{(m+1)(m+3)}{(m-3)(m+3)}\; \; ;\; \; \frac{m+2}{m+3}=\frac{(m+2)(m-3)}{(m-3)(m+3)}\; ;$

$4)\; \; \frac{x}{x+y}=\frac{x(y-x)}{(y-x)(x+y)}\; \; ;\frac{2y^2}{y^2-x^2}=\frac{2y^2}{(y-x)(x+y)} \; \; ;\; \; \frac{y}{x-y}=\frac{-y(x+y)}{(y-x))(x+y)}\\\\5)\; \; \frac{m}{3m-2n}=\frac{m(3m-2n)}{(3m-2n)^2}\; \; ;\; \; \frac{3m^2-3mn}{9m^2-12mn+4n^2}=\frac{3m(m-n)}{(3m-2n)^2}\\\\6)\; \; \frac{a+3}{a^2-2a}=\frac{5(a+3)}{5a(a-2)}\; \; ;\; \; \frac{a-2}{5a-10}=\frac{a(a-2)}{5a(a-2)}\; \; ;\; \; \frac{a+2}{5a}=\frac{(a+2)(a-2)}{5a(a-2)}$

$7)\; \; \frac{3}{3a-3}=\frac{1}{a-1}=\frac{2}{2(a-1)}\; \; ;\; \; \frac{a-1}{2a^2-4a+2}=\frac{a-1}{2\cdot (a-1)^2}=\frac{1}{2\cdot (a-1)}\; ;\\\\8)\; \; 2=\frac{2(m-2)}{m-2}\; \; ;\; \; \frac{14}{m-2}\; \; ;\; \; m=\frac{m(m-2)}{m-2}\; ;\\\\9)\; \; \frac{2x+1}{x^2-6x+9}=\frac{(2x+1)(x+3)^2}{(x-3)^2(x+3)^2} \; ;\; \frac{8}{x^2-9}=\frac{8(x-3)(x+3)}{(x-3)^2(x+3)^2}\; ;\; \frac{2x-1}{x^2+6x+9}=\frac{(2x-1)(x-3)^2}{(x-3)^2(x+3)^2}\; .$