Question

решите неравенства:
1)5-3х<2х+6
2)7-0,6х<20+0,4х
3)5х/4<х/3-2

Answer 1

$1)\; \; 5-3x<2x+6\\\\5-6<2x+3x\\\\-1<5x\\\\5x>-1\\\\x>-0,2\; \; ,\; \; \; x\in (-0,2,+\infty )\\\\\\2)\; \; 7-0,6x<20+0,4x\\\\7-20<0,4x+0,6x\\\\-13<x\\\\x>-13\; \; \; ,\; \; \; x\in (-13,+\infty )\\\\3)\; \; \frac{5x}{4}<\frac{x}{3}-2\\\\\frac{5x}{4}-\frac{x}{3}<-2\\\\\frac{15x-4x}{12} <-2\\\\\frac{11x}{12}<-2\\\\x<\frac{-2\cdot 12}{11}\\\\x<-\frac{24}{11}\\\\x<-2\frac{2}{11}\; \; \; ,\; \; \; x\in (-\infty ,-2\frac{2}{11}\; )$