Question

Я забыл как решать напомните плииз

Answer 1

Ответ:

$2 {x}^{2} - 3x = 4x - 3 \\ 2 {x}^{2} - 3x - 4x + 3 = 0 \\ 2 {x}^{2} - 7x + 3 = 0 \\ 2 {x}^{2} - x - 6x + 3 = 0 \\ x(2x - 1) - 3(2x - 1) = 0 \\ (2x - 1) \times (x - 1) = 0 \\ 2x - 1 = 0 \\ x - 3 = 0 \\ x \frac{1}{2} \\ x = 3 \\ x1 = \frac{1}{2} .x2 = 3$