Question

Найти D (f)

$a)f(x) = \sqrt{ - {x}^{2} + 4 } \\ b)f(x) = \frac{ \sqrt{x {}^{2} - 5x + 6} }{ {x}^{2} - 4} \\ c)f(x) = log_{2}(x + 3) - tg \: x \\ d)f(x) = \frac{(x + 3)(x - 6)}{ \sqrt{36 - 12x + 4} }$
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Answer 1

Объяснение:

а)

$\sqrt{ - x ^{2} + 4 } = 0 \\ - x ^{2} + 4 = 0 \\ x ^{2} = 4 \\ x = 2 \\ x = - 2$

б)