Question

ПАМАГИТИ СРОЧНО!!!!!!!!!!!!!!!!!!!!

Answer 1

Объяснение:

2*a-3*a*b+3*b2=2a-3ab*b2

Answer 2

$1)\; \; 2a-3ab+3b^2=2a-3b(a-b)\\\\2)\; \; 3a^2+\frac{2a+1}{a-5}=\frac{3a^3-15a^2+2a+1}{a-5}\\\\3)\; \; 6a+\frac{3a}{a+1}-\frac{2a+1}{a-3}+a^2=\\\\=\frac{6a(a+1)(a-3)+3a(a-3)-(2a+1)(a+1)+a^2(a+1)(a-3)}{(a+1)(a-3)}=\\\\=\frac{6a^3-12a^2-18a+3a^2-9a-2a^2-3a-1+a^4-2a^2-3a^2}{(a+1)(a-3)}=\frac{a^4+6a^3-16a^2-30a-1}{(a+1)(a-3)}\\\\4)\; \; 2a^2+3ab-\frac{a+b}{a-b}=\frac{2a^2(a-b)+3ab(a-b)-(a+b)}{a-b}=\frac{2a^3-2a^2b+3a^2b-3ab^2-a-b}{a-b}=\\\\=\frac{2a^3+a^2-3ab^2-a-b}{a-b}$