Question

решите неравенство √18х+√2>3х√2+1​

Answer 1

Ответ:

√18 + √2>3√2+1,х≥0

3√2х+√2>3√2+1

3√2х>3√2+1-√2

3√2х>2√2+1

√2х>2√2/3+1/3

√2х>2√2+1/3

2х>(2√2+1)^2/9

2х>8+4√2+1/9

2х>9+4√2/9

х>9+4√2/18,х≥0

х=[9+4√2/18,+бесконечность