Question

-y+25=12y-1
10y+6=12y-8
0,8x+1=1,7x+0,1
12-5(x+1)=7+3x-2x
7(x+3)-2(x-5)=8

Answer 1

Ответ:

-y+25=12y-1,

–y–12y=–1–25,

-13y = -26,

y = 2.

10y+6=12y-8,

10y–12y=–8–6,

-2y = -14,

y = 7.

0,8x+1=1,7x+0,1,

0,8x–1,7x=0,1–1

-0.9x = -0.9

x = 1.

12-5(x+1)=7+3x-2x,

–5x–3x+2x=7+5–12,

x = 0.

7(x+3)-2(x-5)=8,

7x–2x=8–10–21,

5x = -23,

x = -4.6.