Question

Помогите прошу пожалуйста

Answer 1

$16)\frac{3x-2}{x+1}=7\\\\\frac{3x-2}{x+1}-7=0\\\\\frac{3x-2-7x-7}{x+1} =0\\\\\frac{-4x-9}{x+1}=0\\\\\left \{ {{-4x-9=0} \atop {x+1\neq 0}} \right.\\\\\left \{ {{x=-2,25} \atop {x\neq-1 }} \right.\\\\Otvet:\boxed{(-\infty;-2]}$

$17)\sqrt{(\sqrt{3} -2)^{2}}+\sqrt{(\sqrt{3}+2)^{2}}=|\sqrt{3}-2|+|\sqrt{3}+2|=2-\sqrt{3}+\sqrt{3}+2=4\\\\Otvet:\boxed{4}$

$18)x^{3}-2x<(x+2)(x^{2}-2x+4)\\\\x^{3}-2x<x^{3}-2x^{2}+4x+2x^{2}-4x+8\\\\x^{3}-2x<x^{3}+8\\\\x^{3}-2x-x^{3}<8\\\\-2x<8\\\\x>-4\\\\Otvet:\boxed{(-4;+\infty)}$