Question

SOS!!! Помогите решить!!!

Answer 1

Ответ:

$1$

Объяснение:

$\frac{3 {a}^{2} + 2ax - {x}^{2} }{(3x + a)(a + x)} - 2 + 10 \frac{ax - 3 {x}^{2} }{ {a}^{2} - 9 {x}^{2} } = \\ = \frac{3 {a}^{2} + 3ax - ax - {x}^{2} }{(3x + a)(a + x)} - 2 + 10 \frac{x(a - 3x)}{(a - 3x)(a + 3x) } = \\ = \frac{3a(a + x) - x(a + x)}{(3x + a)(a + x)} - 2 + 10 \frac{x}{a + 3} = \\ = \frac{(a + x)(3a - x)}{(3x + a)(a + x)} - 2 + \frac{10x}{a + 3x} = \\ = \frac{3a - x - 2(3x + a) + 10x}{3x + a} = \\ = \frac{3a - x -6x - 2a + 10x }{3x + a} = \\ = \frac{3x + a}{3x + a} = 1$