Question

Помогите, пожалуйста.

Answer 1

Задача 2:

$5 - \frac{1 - 2a}{4} = \frac{3a + 20}{6} + \frac{a}{3} \\ \frac{20 - 1 + 2a}{4} = \frac{9a + 60 + 6a}{18} \\ 18(19 + 2a) = 4(15a + 60) \\ 171 + 18a = 30a + 120 \\ 12a = 51 \\ a = \frac{51}{12} \\ a = 4.25$

Задача 3:

${(3x - 1)}^{2} - (4 {x}^{2} + 5x - 5) + (4 + 7x)(x - 2) = 9 {x}^{2} - 6x + 1 - 4 {x}^{2} - 5x + 5 + 4x - 8 + 7 {x}^{2} - 14x = 12 {x}^{2} - 21x - 2$

Задача 4:

${a}^{5} ( {a}^{4} )^{3} \div {a}^{11} = {a}^{17} \div {a}^{11} = {a}^{6} \\ {a}^{6} = {2}^{6} = 64$